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Comments for Yimin Ge’s Maths Blog
https://yiminge.wordpress.com
Tue, 10 May 2011 06:10:41 +0000
hourly
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Comment on Automorphism Groups of Simple Graphs by Gerd Baron
https://yiminge.wordpress.com/2009/09/26/automorphism-groups-of-simple-graphs/#comment-121
Tue, 10 May 2011 06:10:41 +0000https://yiminge.wordpress.com/?p=164#comment-121They are only isomorphic not identical groups.
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Comment on All Groups of Order n are cyclic iff… by PiterJankovich
https://yiminge.wordpress.com/2009/01/22/all-groups-of-order-n-are-cyclic-iff/#comment-50
Mon, 29 Mar 2010 13:46:24 +0000https://yiminge.wordpress.com/?p=59#comment-50My name is Piter Jankovich. oOnly want to tell, that your blog is really cool
And want to ask you: is this blog your hobby?
P.S. Sorry for my bad english
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Comment on The Sum of Primitive Roots of Unity by Ron Smith
https://yiminge.wordpress.com/2009/06/09/the-sum-of-primitive-roots-of-unity/#comment-48
Tue, 21 Jul 2009 10:32:03 +0000https://yiminge.wordpress.com/?p=156#comment-48Good article of Mobius function.
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Comment on The Sum of Primitive Roots of Unity by tlovering
https://yiminge.wordpress.com/2009/06/09/the-sum-of-primitive-roots-of-unity/#comment-47
Thu, 16 Jul 2009 13:35:36 +0000https://yiminge.wordpress.com/?p=156#comment-47Nice.
Of course, the argument you give is very neat and probably the best. It is, however, possible to verify it directly of course.
If , then since $(k,n)=1 \Leftrightarrow (k+st,n)=1$ the sum is divisible by .
Finally (since is manifestly multiplicative), for any prime , .
So is indeed the Mobius function.
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Comment on All Groups of Order n are cyclic iff… by Cliff Bott
https://yiminge.wordpress.com/2009/01/22/all-groups-of-order-n-are-cyclic-iff/#comment-45
Thu, 18 Jun 2009 18:28:01 +0000https://yiminge.wordpress.com/?p=59#comment-45There is a formula, ascribed to Hölder, that gives the number of (isomorphically distinct) groups of order n, if n is ‘quadratfrei’. The formula is given in the Mathworld article ‘Finite Group’ but I think there are a couple of errors in that version of it. What I think are correct versions are contained in an article ‘Counting Groups…’ by Conway, Dietrich and O’Brien, which is on the web, and in another article, ‘Groups of square-free order are scarce’, by Mays, which is in the Pacific Journal of Mathematics and also on the web. Mays’ article gives a simple worked example of Hölder’s formula (which he ascribes instead to one ‘Balash’) and also refers to the ‘if’ part of your theorem.
If the only (isomorphically distinct) group of order n is the cyclic group, then n is ‘quadratfrei’ and Hölder’s formula applies. Then I think it can probably be shown that Hölder’s formula can only be made to yield the value 1 if your condition, that gcd(n, phi(n)) = 1, holds. Conversely if your condition holds, n is ‘quadratfrei’ and according to Mays, Hölder’s formula yields the value 1 in this case.
The article by Conway et al. gives an outline of how Hölder’s formula can be arrived at. The two papers of Hölder referenced in the Mathworld article can be accessed through the University of Göttingen website but they look like heavy going to me, and on a quick scan I can’t see the formula given explicitly.
Happy problem solving. I look forward to seeing many more beautiful results on your blog. You are exceptionally talented.
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Comment on All Groups of Order n are cyclic iff… by Cliff Bott
https://yiminge.wordpress.com/2009/01/22/all-groups-of-order-n-are-cyclic-iff/#comment-43
Wed, 17 Jun 2009 23:53:36 +0000https://yiminge.wordpress.com/?p=59#comment-43You’re quite right, I misunderstood the proposition. Thanks for clarifying it for me.
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Comment on All Groups of Order n are cyclic iff… by Yimin Ge
https://yiminge.wordpress.com/2009/01/22/all-groups-of-order-n-are-cyclic-iff/#comment-42
Wed, 17 Jun 2009 15:39:13 +0000https://yiminge.wordpress.com/?p=59#comment-42I think you got the statement wrong. The proposition claims that if gcd(n,phi(n))=1 then there do not exist groups of order n that are not cyclic and conversely, if gcd(n,phi(n))>1 then there are some noncyclic groups. For n=4, there is also the Klein four-group which is not cyclic ;-).
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Comment on The Probability of Coprimality by Cliff Bott
https://yiminge.wordpress.com/2009/04/04/the-probability-of-coprimality/#comment-41
Wed, 17 Jun 2009 13:31:19 +0000https://yiminge.wordpress.com/?p=137#comment-41There is a discussion of this and related results in Chapter 18 of Hardy and Wright’s ‘Number Theory’ (5th edition) which you may enjoy. This particular result is their Theorem 332.
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Comment on All Groups of Order n are cyclic iff… by Cliff Bott
https://yiminge.wordpress.com/2009/01/22/all-groups-of-order-n-are-cyclic-iff/#comment-40
Wed, 17 Jun 2009 11:19:55 +0000https://yiminge.wordpress.com/?p=59#comment-40Perhaps I’m overlooking something, but isn’t it the case that there is exactly one cyclic group of every order? There is one cyclic group of order 4 and yet phi(4) = 2 and gcd(4,2) = 2, contradicting your proposition.
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Comment on The Probability of Coprimality by Michalis
https://yiminge.wordpress.com/2009/04/04/the-probability-of-coprimality/#comment-39
Sat, 18 Apr 2009 13:51:08 +0000https://yiminge.wordpress.com/?p=137#comment-39Another interesting theorem slightly related to this one is the following:
Let pt(n) denote the number of primitive pythagorean triples with hypotenuse less than, or equal to n.
Then
I can send you the proof if you want (4 or 5 pages long)