Python - Split String on all punctuations

# Python3 code to demonstrate working of 
# Split String on all punctuations
# using regex + findall()
import re
# initializing string
test_str = 'geeksforgeeks ! is-best, for @geeks'
# printing original String
print("The original string is : " + str(test_str))
# using findall() to get all regex matches. 
res = re.findall( r'\w+|[^\s\w]+', test_str)
# printing result 
print("The converted string : " + str(res)) 

# Python3 code to demonstrate working of
# Split String on all punctuations
# initializing string
test_str = 'geeksforgeeks ! is-best, for @geeks'
# printing original String
print("The original string is : " + str(test_str))
# import string library function
import string
    
# Storing the sets of punctuation in variable result
result = string.punctuation
for i in test_str:
    if i in result:
        test_str=test_str.replace(i,"*"+i+"*")
res=test_str.split("*")
# printing result
print("The converted string : " + str(res))

# Python3 code to demonstrate working of 
# Split String on all punctuations
# Using re.sub() method with lambda function:
import re
# initializing string
test_str = 'geeksforgeeks ! is-best, for @geeks'
# printing original String
print("The original string is : " + str(test_str))
res = re.sub(r'(\W+)', lambda x: ' '+x.group(0)+' ', test_str).split()
# printing result 
print("The converted string : " + str(res))