Python - Check if element is present in tuple

We are given a tuple and our task is to find whether given element is present in tuple or not. For example x = (1, 2, 3, 4, 5) and we need to find if 3 is present in tuple so that in this case resultant output should be True.

Using in Operator

in operator checks if an element is present in a tuple by iterating through its items. It returns True if the element is found and False otherwise making it a simple and efficient membership check.

x = (1, 2, 3, 4, 5) 
# Check if the element '3' is present in the tuple
res = 3 in x  
print(res)  

True

Explanation:

• in operator checks if the element 3 is present in tuple x.
• If element is found it returns True; otherwise it returns False

Using index()

index() method returns the position of the first occurrence of an element in a tuple. If the element is not found it raises a ValueError so it’s often used with exception handling.

t = (1, 2, 3, 4, 5) 
try:
    index = t.index(3) 
    res = True  # If '3' is found
except ValueError:
    res = False  # If '3' is not found
print(res) 

True

Explanation:

• t.index(3) searches for the element 3 in the tuple t and returns its index if found.
• If element is not found a ValueError is raised which is caught to set result to False.

Using a Loop

Using a loop we can iterate through each element of the tuple to check for a match. If target element is found we return True otherwise we return False after checking all elements.

t = (1, 2, 3, 4, 5)  
ele = 3  
res = False  
for item in t:  
    # Check if the current element matches
    if item == ele:   
        res = True  
        break 
print(res)  

True

Explanation:

• Loop checks each element in the tuple for equality with ele. If a match is found res is set to True.
• Break statement stops further iteration once the element is found improving efficiency.