numpy.setxor1d() function in Python

numpy.setxor1d() function find the set exclusive-or of two arrays and return the sorted, unique values that are in only one (not both) of the input arrays.

Syntax : numpy.setxor1d(arr1, arr2, assume_unique = False) Parameters : arr1, arr2 : [array_like] Input arrays. assume_unique : [bool] If True, the input arrays are both assumed to be unique, which can speed up the calculation. Default is False. Return : [ndarray] Sorted 1D array of unique values that are in only one of the input arrays.

Code #1 : Python3

# Python program explaining
# numpy.setxor1d() function
  
# importing numpy as geek 
import numpy as geek 
 
arr1 = [1, 2, 3, 4]
arr2 = [2, 4, 6, 8]
 
gfg = geek.setxor1d(arr1, arr2)
 
print (gfg)

Output :

[1 3 6 8]

  Code #2 : Python3

# Python program explaining
# numpy.setxor1d() function
  
# importing numpy as geek 
import numpy as geek 
 
arr1 = [1, 2, 3, 4, 5]
arr2 = [-2, -1, 0, 1, 2]
 
gfg = geek.setxor1d(arr1, arr2)
 
print (gfg)

Output :

[-2 -1  0  3  4  5]