numpy.ma.is_mask() function | Python

numpy.ma.is_mask() function return True if parameter m is a valid, standard mask. This function does not check the contents of the input, only that the type is MaskType. In particular, this function returns False if the mask has a flexible dtype.

Syntax : numpy.ma.is_mask(m) Parameter : m : [array_like] Array to check. Return : [bool] True if m.dtype.type is MaskType, False otherwise.

Code #1 : Python3

# Python program explaining
# numpy.ma.is_mask() function
# importing numpy as geek 
# and numpy.ma module as ma 
import numpy as geek 
import numpy.ma as ma 
m = ma.masked_equal([0, 1, 2, 0, 3], 0)
gfg = ma.is_mask(m)
print (gfg)

Output :

False

  Code #2 : Python3

# Python program explaining
# numpy.ma.is_mask() function
# importing numpy as geek 
# and numpy.ma module as ma 
import numpy as geek 
import numpy.ma as ma 
m = [True, False, True]
gfg = ma.is_mask(m)
print (gfg)

Output :

False