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Project Euler, Problem #1, C - Pastebin.com
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- /* Если выписать все натуральные числа меньше 10, кратные 3 или 5, то
- получим 3, 5, 6 и 9. Сумма этих чисел равна 23. Найдите сумму всех
- чисел меньше 1000, кратных 3 или 5. */
- #include <stdio.h>
- int main()
- {
- int i;
- int s = 0;
- for(i = 0; i < 1000; i++)
- {
- if(i % 3 == 0 || i % 5 == 0)
- s+=i;
- }
- printf("%d\n", s);
- return(0);
- }
- // 233168
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