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ORA-XQ-282-B: sort order of results of a step expression from Stephen Buxton on 2004-02-16 (public-qt-comments@w3.org from February 2004)
ORA-XQ-282-B: sort order of results of a step expression
- From: Stephen Buxton <Stephen.Buxton@oracle.com>
- Date: 16 Feb 04 14:19:02
- To: public-qt-comments@w3.org
- Cc:
- Message-Id: <200402162219.i1GMJ2217341@rgmgw6.us.oracle.com>
SECTION 3.2: Path expressions It says in the third paragraph after rule [70] that "Each operation E1/E2 is evaluated as follows: expression E1 is evaluated... The sequence of nodes resulting from all evaluations of E2 are combined, eliminating duplicate nodes based on node identity and sorting the result in document order". Later, in section 3.2.1 "Steps", in the last paragraph prior to the final note, it says "If the axis is a reverse axis, context positions are assigned in reverse document order." These two sentences appear to be in contradiction. Either reverse axes result in a sequence that is in forward document order, or the general statement in 3.2 should say that the result is in either forward or reverse document order. - Steve B.
Received on Monday, 16 February 2004 17:19:05 UTC