String.prototype.endsWith()

Try it

const str1 = "Cats are the best!";
console.log(str1.endsWith("best!"));
// Expected output: true
console.log(str1.endsWith("best", 17));
// Expected output: true
const str2 = "Is this a question?";
console.log(str2.endsWith("question"));
// Expected output: false

Syntax

endsWith(searchString)
endsWith(searchString, endPosition)

Parameters

searchString

The characters to be searched for at the end of str. Cannot be a regex. All values that are not regexes are coerced to strings, so omitting it or passing undefined causes endsWith() to search for the string "undefined", which is rarely what you want.

endPosition Optional

The end position at which searchString is expected to be found (the index of searchString's last character plus 1). Defaults to str.length.

Return value

true if the given characters are found at the end of the string, including when searchString is an empty string; otherwise, false.

Exceptions

TypeError

Thrown if searchString is a regex.

Description

This method lets you determine whether or not a string ends with another string. This method is case-sensitive.

Examples

Using endsWith()

const str = "To be, or not to be, that is the question.";
console.log(str.endsWith("question.")); // true
console.log(str.endsWith("to be")); // false
console.log(str.endsWith("to be", 19)); // true

Specifications

Browser compatibility

See also

• Polyfill of String.prototype.endsWith in core-js
• es-shims polyfill of String.prototype.endsWith
• String.prototype.startsWith()
• String.prototype.includes()
• String.prototype.indexOf()
• String.prototype.lastIndexOf()