Sort Tuple of Lists in Python

The task of sorting a tuple of lists involves iterating through each list inside the tuple and sorting its elements. Since tuples are immutable, we cannot modify them directly, so we must create a new tuple containing the sorted lists. For example, given a tuple of lists a = ([2, 1, 5], [1, 5, 7], [5, 6, 5]).The goal is to generate a new tuple where each list inside the tuple is sorted. The resulting tuple will be ([1, 2, 5], [1, 5, 7], [5, 5, 6]) .

Using list comprehension

When sorting a tuple of lists, list comprehension provides a efficient approach. It allows us to iterate through the tuple, apply sorting to each list, and create a new tuple with the sorted lists.

a = ([2, 1, 5], [1, 5, 7], [5, 6, 5])
res = tuple([sorted(i) for i in a])
print(res)

([1, 2, 5], [1, 5, 7], [5, 5, 6])

Explanation: list comprehension iterate through each list in the tuple a, applying the sorted() to each list. The result is a new list of sorted lists, which is then converted back into a tuple using tuple().

Using map()

map() is another popular method for applying a function to each item in an iterable. In the case of sorting a tuple of lists, we can use map() to apply the sorted() to each list within the tuple and then convert the result back into a tuple.

a = ([2, 1, 5], [1, 5, 7], [5, 6, 5])
res = tuple(map(sorted, a))
print(res)

([1, 2, 5], [1, 5, 7], [5, 5, 6])

Explanation: map() applies sorted() to each list in the tuple a and tuple() converts the result into a tuple of sorted lists.

Using lambda function

Lambda functions provide a flexible way to define small, anonymous functions for specific tasks. When combined with map(), we can use a lambda function to apply sorting to each list inside the tuple.

a = ([2, 1, 5], [1, 5, 7], [5, 6, 5])
res = tuple(map(lambda x: sorted(x), a))
print(res)

([1, 2, 5], [1, 5, 7], [5, 5, 6])

Explanation: map() applies a lambda function to each list in the tuple a, where the lambda function sorts each list using sorted(x). The result is then converted into a tuple using tuple() .

Using for looop

While less concise, for loop gives us more control over the sorting operation. In this approach, we iterate through the tuple, sort each list and then collect the sorted lists into a new tuple.

a = ([2, 1, 5], [1, 5, 7], [5, 6, 5])
res = []  # Initialize an empty list
for i in a:
    res.append(sorted(i))
res = tuple(res)
print(res)

([1, 2, 5], [1, 5, 7], [5, 5, 6])

Explanation: for loop iterates over each list i in the tuple a and sorted(i) sorts the list. The sorted list is then appended to the list res, which will later be converted into a tuple.